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IBM Developing with IBM Enterprise PL/I Sample Questions:

1. Which of the following steps is NOT required to use the IBM Debug Tool on a PL/I program?

A) Have the source code available
B) Write an Language Environment user condition handler
C) Plan points where the program should stop during testing
D) Compile with TEST option

2. A program reads an input file into a structure with 20 fields. Fifteen of these are required as parameters in
an external procedure. Which of the following is the most efficient way of passing these parameters?

A) Create a structure, assign the 15 variables to it and pass it as one argument.
B) Pass 15 variables in a parameter list.
C) Pass the address of the input structure as one argument.
D) Create a structure, assign the 15 variables to it and pass the address of it in one argument.

3. Input to a SORT routine requires the starting position of each field to be sorted. Which of the following
calculates a value of 5 for field B?
DCL 1 S,
2 A CHAR(4),
2 B BIN FIXED(31);

A) POINTERDIFF(ADDR(S), ADDR(S.B)) + 1
B) POINTERDIFF(ADDR(S), ADDR(S.B))
C) POINTERDIFF(ADDR(S.B), ADDR(S))
D) POINTERDIFF(ADDR(S.B),ADDR(S)) + 1

4. A member of the team points out to the lead developer that there appears to be an error in the program
the lead developer has created. Which of the following is the most appropriate response from the lead
developer?

A) Thank the programmer, indicating there is not time to correct the code and requesting that he do so.
B) Thank the programmer, asking for details about the error and discussing the solution with him.
C) Thank the programmer, saying the program will be checked but asking him to check that the error is
not in his program.
D) Thank the programmer, indicating the code will be revised and provided to the team for review.

5. Given the following code whatwill be output, if an,thing?
DCLX FIXED DEC(5,2) INIT (-123.45);
DCL S CHAR (7);
PUT STRING (S) EDIT(X) (A(7));
PUT DATA (5);

A) The program ends abnormally at runtime with condition CONVERSION.
B) S='123.45'
C) S='-123.45';
D) S=' -123.4'

Solutions: